Q&A: HOW DO I JUDGE HOW MANY VIEWS I HAVE? IT’S RANKED IN THE TOP 3 SITES FOR 2 KEYWORDS ON GOOGLE FOR A YEAR.?

Question by Larry:
How do I judge how many views I have? It’s ranked in the top 3 sites for 2 keywords on Google for a year.?
I have a letter posted as content on 1 page of someone else’s website. ‘Google searches’ show it to rank within the top 3 sites for 2 keywords for over a year now. Is there any way I can learn how many visitors it has – without posting a visitor counter script on this other person’s site?
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Answer by tauro22
Contact the owner of the site and ask them very nicely whether they could possibly check their traffic stats to see how many times that page has been viewed recently.
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Give your own answer to this question below!









about 2 years ago
There are many different ways depending on which technologies you are using (e.g. java, php etc.). But essentially you create an html form for your inputs which will submit to a server side script that you have on your server.
This server side script will pull out the variable values from your form submission and then replace them in your template. You may do this simply by using String handling and some regex, this would be the quick and dirty way (in general this completely depends on what server side technologies are in play). You may pretty easily do this with Java using a templating engine like Velocity. The script will then return the html source with all the variables replaced back to the browser where it will be rendered.
about 2 years ago
You may like to take a tutorial at
http://referencedesigner.com/tutorials/html/html_1.php
about 1 year ago
You said visitor counter script. I am assuming you mean a visible counter. Google actually has an analytical service which is a snippet of code that can be added to the site and this Google collects very detailed data about where the users came from, browser they were using, etc. etc. Very informative. The code that you add to the site is invisible to users.
This analytical service can be accessed in Google’s Adwords.
about 1 year ago
have you tried Alexa.com?